Question

Use the discriminant to determine the number and type of solutions the equation has.



x2 + 6x + 12 = 0

Answer 1

A.
two rational solutions


B.
one real solution


C.
two irrational solutions


D.
no real solution

Answer 2

@aaronq

Answer 3

@tHe_FiZiCx99

Answer 4

@iambatman

Answer 5

I think it is No Real Solution

Answer 6

Well you know what the discriminant is right?

Answer 7

How to get it yea

Answer 8

Do you know how to do this? The discriminant formula comes from the quadratic formula and is b^2 - 4ac. If it is = 0 it has one real solution. If it is > 0 it has 2 real solutions. If it is < 0 it has two complex nonreal solutions that are conjugates of one another. So let's see what this discriminant equals. In your quadratic equation, a = 1, b = 6 and c = 12. b^2 - 4ac --> (6)^2 - 4(1)(12) --> 36 - 48 = -12. So it has two complex nonreal solutions. So it is C.

Answer 9

^ I was basically typing, that, so yeah he's right.

Answer 10

Ok lol, thanks

Answer 11

If the value is 0 there are two real equal roots
If the value is less than 0 than there are two unequal complex roots
If the value is greater than 0 than there are two real unequal roots
In a nutshell.

Answer 12

the discriminant is the \(\ \sf \Large \sqrt{b^2 - 4ac} \) part of the quadratic formula. If you have a positive number then you'll have 2 solutions. If you have a negative number you won't have any solutions, by solutions I mean real number solutions. You'd have complex which would be something like \(\ \sqrt{-1} \). If you have one that's equal to zero you have 2 solution's, they're just the same to some people consider them to have one solutions when the discriminant is equal to zero.

Answer 13

Thanks you 3.

Answer 14

Yw, I guess

Answer 15

That's good, you have many sources now :)

Answer 16

Yea, you helped me understand it better

Answer 17

Is your pic suppose to be a reference to hartnn?