The population of a local species of bees can be found using an infinite geometric series where a1 = 860 and the common ratio is one fifth. Write the sum in sigma notation and calculate the sum (if possible) that will be the upper limit of this population.
@SolomonZelman
for how many terms?
Not sure doesn't say, that's all the information provided
@mathmale Can you help? Solomon seems to of gotten offline.
Hello! Have you any previous experience with geometric series, and particularly with finding the sum of a geometric series when certain conditions are met?
Somewhat, I've learned about it but never fully understood it. I'm taking a timed "exam" (they call it exam but it's mostly just an assigment with 15 questions) and I'm getting stumped.
If r is the common ratio of a geometric series, and a is the first term of that series, a formula for the sum of that series (if and only if |r|<1 ) is given by\[\frac{ a }{ 1-r}\]
In the problem at hand, what is a? what is r? what is 1-r? and, finally, what is a / (1-r)?
a is 860? and r will be...the 1/5?
That's right. Go ahead and calculate the rest.
I got 1, 075
The "sum of a geometric series" is a limit, the limit that one reaches by summing up an infinite numberf of terms. Your result represents such a limit here, and is correct.
So would my response be \[\sum_{?}^{?} 860\left(\begin{matrix}1 \\ 5\end{matrix}\right)^{i-1} the sum is 1, 075?
Sorry, that came out wrong I'll try that again. \[\sum_{?}^{?} 860 \left(\begin{matrix}1 \\ 5\end{matrix}\right) \]
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