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A line contains the points (8, 9) and (–12, –7). Using point-slope form, write the equation of the line that is parallel to the given line and that passes through (–5, –15)
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first, calculate the slope of the line through (8, 9) and (–12, –7)... what is it?
4/5
good... so 4/5 is the slope of the line you want AND it needs to go through the point (-5,-15)... plug this into the point-slope form and what u got???
HINT: point-slope form: \(\large y-y_0=m(x-x_0) \), where \(\large (x_0,y_0) \) is the given point.
y+15=4/5(x+5)
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yep... good work.
thank you for helping me out :)
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