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Mathematics 16 Online
OpenStudy (anonymous):

Find the LCM of 18 x^2 y^4 and 30x^5 y^3

OpenStudy (anonymous):

6x^2y^3 18x^2y^4 30x^5y^3 3y 5x^3 =(6x^2y^3)*(3y)*(5x^3)

OpenStudy (anonymous):

so for lcm you have to break the numbers down to prime factorization 18 6 3 2 3 3 30 5 6 5 2 3

OpenStudy (anonymous):

the set of numbers both have a 2 and the most 2 any of them have is one so you include one 2 the next number is 5 and only one of them has a 5 and the number of 5 is one so you include one 5 the next number is a 3 and they both have a 3, the most most number of 3 is two so you include two number 3 2*5*3*3=90

OpenStudy (anonymous):

you do the same with the the variables, you look at both take the ones with the highest power x^5*y^4

OpenStudy (anonymous):

so your answer is 90x^5*y^4

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