Question

Few questions please help?!

Answer 1

1. Use the given values to evaluate the remaining trigonometric functions. \[cscx=\sqrt{17},tanx=-\frac{ 1 }{ 4 }\]

2. Find all solutions of the equation in the interval [0, 2π). \[\tan^2x-secx=-1\]

3. Given a triangle with side lengths a = 9, b = 3, and c = 11, find the measure of angle A.

4. Factor the expression and use the fundamental identities to simplify. \[\cos^2xsin^2x-\cos^2x\]

Answer 2

Hint: csc = 1/sin

Answer 3

3.\[\cos A=\frac{ b^2+c^2-a^2 }{ 2bc }\]
4. take common\[-\cos ^2x\]

Answer 4

@surjithayer how do I do #4?

Answer 5

\[-\cos ^2x \left( -\sin ^2x+1 \right)=-\cos^2x \cos ^2x=-\cos ^4x\]

Answer 6

Thanks do you know how to do the first 2?

Answer 7

\[\csc x=\sqrt{17},\sin x=\frac{ 1 }{ \sqrt{17} }\]

Answer 8

\[\tan x=-\frac{ 1 }{ 4 },\cot x=-4\]

Answer 9

\[\cot x=-4,\frac{ \cos x }{ \sin x }=-4,\cos x=-4 \sin x=-4*\frac{ 1 }{ \sqrt{17} }\]

Answer 10

\[\sec x=-\frac{ \sqrt{17} }{ 4 }\]

Answer 11

Thank you @surjithayer !

Answer 12

yw