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Mathematics 17 Online
OpenStudy (anonymous):

WILL FAN AND MEDAL!! Dilation problem!!! Polygon MNOPQ is dilated by a scale factor of 0.8 with the origin as the center of dilation, resulting in the image M′N′O′P′Q′. If M = (2, 4) and N = (3, 5), what is the slope of line M'N'?

OpenStudy (anonymous):

\[A. \sqrt{2} \] \[B. 1\] \[C.\sqrt{3}\] \[D.\sqrt{\frac{ 1 }{ 2 }}\]

OpenStudy (anonymous):

@AccessDenied @sourwing @ganeshie8 @jim_thompson5910 some please help

OpenStudy (anonymous):

@saifoo.khan

OpenStudy (saifoo.khan):

Tried plotting?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

http://www.mathway.com/graph/MjY3MTU

OpenStudy (anonymous):

I don't understand how to find the slope

OpenStudy (anonymous):

using 2 given points. Could I use the distance formula? @AccessDenied

OpenStudy (accessdenied):

We're looking for slope, right? Slope between the two dilated points, M' and N'. So if we first found M' and N', we have to use the formula for slope rather than the formula for distance.

OpenStudy (anonymous):

okay, with the distance formula I got \[\sqrt{2}\]

OpenStudy (anonymous):

\[slope=\frac{ y2-y1 }{ x2-x1}=\frac{ 5-4 }{ 3-2 }=\frac{ 1 }{ 1 }=1\]

OpenStudy (accessdenied):

Yup, that's the one we'd want to answer the question: " what is the slope of line M'N'? " But here we were using M and N, while M' and N' are the already-dilated points. Luckily, if we multiplied everything by a scaling factor like 0.8, it just becomes excess: \( \dfrac{5 - 4}{3 - 2} \iff \dfrac{5\times 0.8 - 4 \times 0.8}{3 \times 0.8 - 2 \times 0.8} = \dfrac{0.8}{0.8} \dfrac{(5 - 4)}{(3 - 2)} \)

OpenStudy (anonymous):

so multiply (5-4) by 0.8? and (3-2) by 0.8?

OpenStudy (anonymous):

@AccessDenied I got 1

OpenStudy (accessdenied):

I agree with slope = 1. :) What's strange is that most options seem to have a square root involved, as if using distance formula. But the question asks for slope. o.O

OpenStudy (anonymous):

That is were they trick you.

OpenStudy (anonymous):

I guess it's where they see the 2 given points, and forget about the slope. That's what I done.

OpenStudy (accessdenied):

Yea, I guess so! Really if you have integer coordinates and it said "find slope," you wouldn't even need to do work if 3/4 choices were square roots. Slope is all fractions and subtracting, so no square roots unless the coordinates have them... lol

OpenStudy (anonymous):

Ill remember that next time :)

OpenStudy (accessdenied):

It's a good thought for some problems, just don't forget how to do the problem in case they decide to throw a second curve ball (now there's only one square root in the distance problem [square roots can simplify to integers]!). ;)

OpenStudy (anonymous):

;) okay, I still have 4 more dilation questions:/

OpenStudy (accessdenied):

Hm, what's next?

OpenStudy (anonymous):

I just posted it

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