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Medal! Please match the equation to the graph, also please show me how you got that answer. I would like to understand. y=x^2 y=2x^2 y=2x^2 y=2(2)^x attachment below
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see from the graph select any two points where you can identify both x,y let us take (-1,1) and (1,4) here in the graph , at x=-1, y=1 and at x=1,y=4 so substitute x and y in the options and check for correct function
since the graph is not shaped like a U it is not going to be any version of x^2
the most likely choice is of the form A k^x such that: A k^0 = 2 and: A k^1 = 4 what is A and k ?
so it would be y=2(2)^x?
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2(2)^x?
right!!!
thanks!!
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