Mathematics
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OpenStudy (anonymous):
SIMPLIFY??
3√45 - 8√20
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OpenStudy (anonymous):
@jim_thompson5910 helpp?(:
OpenStudy (dbzfan836):
-15.6524758425
jimthompson5910 (jim_thompson5910):
how would you simplify \(\Large \sqrt{45}\)
OpenStudy (anonymous):
@jim_thompson5910 you can't right? but the square root of 45 is 6.70
jimthompson5910 (jim_thompson5910):
can you factor 45 into two numbers where one of them is a perfect square?
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OpenStudy (anonymous):
@jim_thompson5910 yes 9 and 5, 9 would be the perfect square
jimthompson5910 (jim_thompson5910):
good
jimthompson5910 (jim_thompson5910):
so
\[\Large \sqrt{45} = \sqrt{9*5}\]
OpenStudy (anonymous):
@jim_thompson5910 okay..
jimthompson5910 (jim_thompson5910):
then you use the rule \[\Large \sqrt{x*y} = \sqrt{x}*\sqrt{y}\]
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jimthompson5910 (jim_thompson5910):
\[\Large \sqrt{45} = \sqrt{9*5}\]
\[\Large \sqrt{45} = \sqrt{9}*\sqrt{5}\]
\[\Large \sqrt{45} = ???\]
OpenStudy (anonymous):
@jim_thompson5910 i don't know :(
OpenStudy (anonymous):
3√45 - 8√20
= 3√9*5 - 8√4*5
= 9√5 - 16√5
= -7√5
I go this from Yahoo Answers, does it help? It helped me. :)
jimthompson5910 (jim_thompson5910):
Do you see how I got
\[\Large \sqrt{45} = \sqrt{9*5}\]
\[\Large \sqrt{45} = \sqrt{9}*\sqrt{5}\]
OpenStudy (anonymous):
@jim_thompson5910 yes I see you used the equation from above..
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jimthompson5910 (jim_thompson5910):
what is the square root of 9
OpenStudy (anonymous):
@CrazyCountryGirl thanks but I need a little more in depth help. :)
OpenStudy (anonymous):
@jim_thompson5910 3 is the square root of 9
jimthompson5910 (jim_thompson5910):
so,
\[\Large \sqrt{45} = \sqrt{9*5}\]
\[\Large \sqrt{45} = \sqrt{9}*\sqrt{5}\]
\[\Large \sqrt{45} = 3*\sqrt{5}\]
OpenStudy (anonymous):
OK. :) Sorry I couldn't help more.
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OpenStudy (anonymous):
@jim_thompson5910 oh okay i see..
jimthompson5910 (jim_thompson5910):
so how would you simplify \[\Large \sqrt{20}\]
OpenStudy (anonymous):
it would be 5 and 4 where 4 is the perfect square. and it would be √20= √5*4
jimthompson5910 (jim_thompson5910):
so far so good
OpenStudy (anonymous):
√20 = √5 √4
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jimthompson5910 (jim_thompson5910):
keep going
OpenStudy (anonymous):
@jim_thompson5910 so it would be √20 = 2*√5
jimthompson5910 (jim_thompson5910):
good
jimthompson5910 (jim_thompson5910):
summing up we have so far
\[\Large \sqrt{45} = 3*\sqrt{5}\]
\[\Large \sqrt{20} = 2*\sqrt{5}\]
jimthompson5910 (jim_thompson5910):
those two facts allow us to go from
\[\Large 3*\sqrt{45} - 8*\sqrt{20}\]
to
\[\Large 3*3*\sqrt{5} - 8*2*\sqrt{5}\]
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OpenStudy (anonymous):
@jim_thompson5910 so it would be 9 * √ 5 - 16 * √ 5
jimthompson5910 (jim_thompson5910):
good, what's next?
OpenStudy (anonymous):
then you subtract 9-16 and it would be -7√5
OpenStudy (anonymous):
@jim_thompson5910 thank you so much. :) saved my life.. haha
jimthompson5910 (jim_thompson5910):
you're welcome