if 4x^2y^2+8x^3y^5 over 2xy^2 is completely simplified to 2xayb + 4xcyd, where a, b, c, and d represent integer exponents, what is the value of c?

Question

ranga · Answer

Shouldn't it be 2x^ay^b + 4x^cy^d ?

anonymous · Answer

$\Large \frac{4x^2y^2+8x^3y^5}{2xy^2}=\frac{4x^2y^2}{2xy^2}+\frac{8x^3y^5}{2xy^2}=2x+4x^2y^3$
Thus, $\Large a=1, b=0,c=2,d=3 $

anonymous · Answer

$\Large y^0=1$

anonymous · Answer

@ranga no the equation itself is correct, I copied and pasted it.

ranga · Answer

The equation is correct but I think the part "simplified to 2xayb + 4xcyd"  should be: "simplified to 2x^ay^b + 4x^cy^d".  (the ^s are missing).

anonymous · Answer

ooh I see what your saying, yes your right :3