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Mathematics 21 Online
OpenStudy (anonymous):

to prove writing question below *sighs*

OpenStudy (anonymous):

if \[u = (\frac{ 1 }{ \sqrt{5} },(\frac{ -1 }{ \sqrt{5} }) ,v=(\frac{ 2 }{ \sqrt{30} },(\frac{ 2 }{ \sqrt{30} })\] show that {u,v} is orthonormal if \[IR^2\] has inner product \[<u,v> = 3u_1v_1+2u_2v_2\] but not orthonormal if \[IR^2\] has the euclidean inner product

OpenStudy (anonymous):

so boring to type this all

OpenStudy (anonymous):

haha well instead of typing it , can u take a snap ?

OpenStudy (anonymous):

-.- i think thats a very nice idea

OpenStudy (anonymous):

so do you know how to solve it? @BSwan @dan815

OpenStudy (anonymous):

well , its direct just apply the given inner product whats ur course name ?

OpenStudy (dan815):

yah

OpenStudy (dan815):

dot product is just x1x2+y1y2

OpenStudy (dan815):

for euclidian

OpenStudy (anonymous):

computer science n it has maths in it -.-

OpenStudy (anonymous):

the course name CS ? weird hehe

OpenStudy (anonymous):

oh you both know the answer,give each other a medal i am graduating in computer science

ganeshie8 (ganeshie8):

whats \(IR^2\) ?

OpenStudy (anonymous):

lol i dnt care for medal or answer i gave u a hint why dnt u try to solve :D

OpenStudy (anonymous):

IR as in real number @ganeshie8 and IR^2 as in 2 dimensional

OpenStudy (anonymous):

@BSwan yeah i will solve it,seems like it was easy afterall

OpenStudy (anonymous):

IR^2 I : identity (0,0) for addition (1,0) , (0,1) for multiplication R^2 domain ( R *R ) means both x,y in u and v are real

ganeshie8 (ganeshie8):

lol okie :) this one \(\large \mathbb R\)

OpenStudy (anonymous):

yeah for n dimention :- its IR^n

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