Question

Find the volume of the frustum of a regular pyramid with hexagonal bases whose sides are 4 cm and 6 cm and a height of 12 cm

Answer 1

@ganeshie8

Answer 2

@kx2bay

Answer 3

The volume of a pyramid is (1/3) × (area of the base) × height,now find the area

Answer 4

this is a frustum, not a full pyramid

Answer 5

okay then

Answer 6

pffft i know
am telling her stepwise
The volume of the frustum is then the difference of the volumes of two hexagonal pyramids

Answer 7

Area of the Base (larger) hexagon =
\[\frac{ 3\sqrt{3} }{ 2 } a ^{2}\] and a = 6
can you work it out? what did you get for it?

Answer 8

93.53

Answer 9

then what next

Answer 10

excellent!
Can you find the area of the smaller base where a = 4 ?

Answer 11

41.57 then what next step

Answer 12

good.
http://www.ditutor.com/solid_gometry/frustum_pyramid.html

Volume of the frustum =

\[V = \frac{ h }{ 3 } ( A + A' + \sqrt{A.A'} )\]

h = 12
A = 95.53
A' = 41.57
V = ?

Answer 13

sorry typo A = 93.53

Answer 14

v = 789.8

Answer 15

whats the unit

Answer 16

cm squared
well done

Answer 17

oh okay thanks godbless always how about this A pyramid whose base is enclosed by a regular hexagon of side 5 cm and whose altitude is 25 m is cut by a plane parallel to the base and 5 cm from the base what is the volume of the frustum formed?

Answer 18

post the second question seperately, not here

Answer 19

okay