Question

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Answer 1

If a and b are the roots of ax^2 + bx +c =0 (\[a \neq 0\] and a+d , b+d are the roots of
Ax^2 + Bx + C =0 \[a \neq 0\] for some constant d , then prove that
\[\frac{ b ^{2}- 4ac }{ a ^{2} } =\frac{ B ^{2} -4AC }{ A ^{2} }\]

Answer 2

I will come back shortly after dinner sorry:)

Answer 3

:) nice one lol
all todday Qn have ratios xD

Answer 4

-B/A = sum of roots = a+b+2d

C/A = product of roots = (a+d)(b+d)

you can use this

Answer 5

You may also express (b^2 - 4ac)/a^2 as (-b/a)^2 - 4(c/a)

Answer 6

Ax^2 + Bx + C = a(x-d)^2 + b(x-d) + c

Answer 7

hartnn + shubam's hints give u fastest solution ^

Answer 8

I will try doing it

Answer 9

I'll give u the donkey way of doing anyways cuz its kindof cool too :)

Ax^2 + Bx + C = a(x-d)^2 + b(x-d) + c
= ax^2 + (b-2ad)x + (ad^2-bd + c)

B^2 - 4AC = (b-2ad)^2 - 4a(ad^2 - bd +c)
= b^2 - 4ac

QED.