Question

Find the zeros of the function.

f(x) = 8x3 + 40x2 + 48x
PLEASE HELP!! MEDAL!!!!!!!

Answer 1

You can do it in many ways...If you know calculus, then just differentiate the function...the thing that will be left....factorize it and find out the values of x for which the function will give zero...

Answer 2

set f(x)=0, factor out of 8x and then solve the quadratic by factoring

Answer 3

0 is one right?

Answer 4

so are the zeros 0,2, and 3?

Answer 5

@SolomonZelman am i right?

Answer 6

\(\large\color{black}{ \bf f(x) = 8x^3 + 40x^2 + 48x}\)

\(\large\color{black}{ \bf 8x^3 + 40x^2 + 48x=0}\)
\(\large\color{black}{ \bf 8x(x^2 + 5x + 6x)=0~~~~~~~~~~8x=0~~->~~x=0,}\)

\(\large\color{black}{ \bf x^2 + 5x + 6x=0}\)
\(\large\color{black}{ \bf (x+2)(x+3)=0~~~~~~~~~~x=~-2,~~-3~}\)

Answer 7

8x(x^2+5x+6)

Answer 8

@SolomonZelman I liked that answer. It was very \(\mathbb{bold}\)ly given. :D

Answer 9

@SolomonZelman

Answer 10

so the zeros are 0, -2, and -3? @SolomonZelman

Answer 11

@SolomonZelman are those the zeros?

Answer 12

yes