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Mathematics 22 Online
OpenStudy (anonymous):

Which set of data shows forty percent as the experimental probability of a particular traffic light being green on your way to school in the morning? 4 of twenty-five selections at random from a card deck being a black card, with black representing a green light 8 tails in twenty coin flips, with tails representing a green light 5 odd-numbers in 8 rolls of a standard die, with odd numbers representing a green light spinning ten vowels out of forty spins of a spinner with 6 equally divided sections labeled with 3 vowels and 3 consonants

OpenStudy (anonymous):

@Drsuz98

OpenStudy (anonymous):

@MelissaHolmes

OpenStudy (anonymous):

@Drsuz98

OpenStudy (anonymous):

The first oneeeee...;D @hippo4

OpenStudy (anonymous):

A local radio station is researching radio listening habits. The station manager surveys listeners who call in to request songs. Which of the following represents the sample? all of the listeners surveyed all of the listeners listeners in the eighteen to twenty-four age range one listener

OpenStudy (anonymous):

Im pretty sure it would be listeners in the eighteen to twenty-four age range..what would u do without me..lol

OpenStudy (anonymous):

last 2 @Drsuz98

OpenStudy (anonymous):

If you made a circle graph with percentages from this tally table, what label would the segment for Car have? A frequency table with a column for commercials and one for tallies. For Car Commercials, there are ten tally marks. For Retail Commercials, there are thirteen tally marks. For TV Show Commercials, there are nineteen tally marks. For Event Commercials, there are eight tally marks. ten twenty percent five ten percent

OpenStudy (anonymous):

ten percent

OpenStudy (anonymous):

Which of the following is an overlapping event with a probability of fifty percent? A spinner is divided into eight equal sections. Four are shaded red and four are shaded blue with each color alternating (red, then blue, then red…). The red sections are labeled B, F, M, and T. The blue sections are labeled A, E, O, and U. Spinning the letter B or the letter O. Spinning red or the letter A. Spinning the letter M or red. Spinning a consonant or blue.

OpenStudy (anonymous):

i think it would be Spinning the letter B or the letter O.

OpenStudy (anonymous):

last one like ffor reals then i can finish a skate video @Drsuz98

OpenStudy (anonymous):

Okay..i dont mind helping u..it makes me feel kinda smart..lol

OpenStudy (anonymous):

A spinner is divided into ten equal segments. The segments are labeled with the letters A, B, E, I, L, M, O, S, T, U. Match each compound event with its probability. Match Term Definition Probability of A and A A) zero point one percent Probability of vowel and consonant B) one percent Probability of M and E and T C) twenty-five percent Probability of a letter before J and a letter after R D) twelve percent can u match these

OpenStudy (anonymous):

Probability of vowel and consonant is one percent..

OpenStudy (anonymous):

Probability of a letter before J and a letter after R is twenty five percent Probability of M and E and T is twelve percent and of course Probability of A ..zero point one percent @hippo4

OpenStudy (anonymous):

and Im not sure if those r completely correct..I tried my best!!....and is this geometry?

OpenStudy (anonymous):

@hippo4

OpenStudy (anonymous):

yep

OpenStudy (anonymous):

okayy..what else..? @hippo4

OpenStudy (anonymous):

Sara selects two cards at random from a standard deck of fifty-two cards. Which of the following could be used to calculate the probability that she will select two numbered cards if she replaces the first card before selecting the second? Note: For this problem, face cards and aces are not numbered cards. thirty-six over fifty-two times thirty-five over fifty-one thirty-six over fifty-two times thirty-five over fifty-two thirty-six over fifty-two times thirty-six over fifty-two thirty-six over fifty-two times thirty-six over fifty-one

OpenStudy (anonymous):

@Drsuz98

OpenStudy (anonymous):

@Drsuz98

OpenStudy (anonymous):

omg, I'm sorry I didn't respond... I was not online :( if you still need the last one .... Number of cards: 52 Number of even cards: 4 suits x 5 numbers (2, 4, 6, 8, 10) = 20 * Face cards are only J, Q, K Step 1: Selecting the first card w/o replacement: Probability of even = 20 / 52 Step 2: Selecting the second card w/o replacement Probability of even = (20-1) / (52-1) *after step 1, there is one less even card Total probability = Step 1 x Step 2.

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