Inscribed angles help please. http://gyazo.com/f21d5a3edb12d480742a7eebbfe7cd40
@e.mccormick Hello! Would you mind helping me real quick? Sorry to bother you.
@Hero Hello! Would you mind helping maybe? Sorry to bother you though!
Here is a reference to all the inscribed angle formulas: http://www.regentsprep.org/Regents/math/geometry/GP15/CircleAngles.htm
I've read sites like that and I only get more confused, thank you though. I appreciate it.
Well, it comes down to using the correct formula. Now, one thing to work out is what that \(110^\circ\) is for.
I'm not quite sure what it would be for. I'm extremely lacking in the math area.
Now, one thing you can learn from that page is this: |dw:1401298020647:dw|
Now, that \(S^\circ\) looks like it is just a portion of that. But hard to say if it is to scale or what.
Okay.. I think I understand that much.
AH! OK, I see what the 110 is for! |dw:1401298429015:dw| That arc. From that, you can find the angle opposite. Then s = 90 - angle opposite the 110.
Uh, I may get that. I thnk.
So that brings to this: |dw:1401298532984:dw| If I have angle A and intercepted arc S, then \(\measuredangle A = \dfrac{1}{2}S \)
So can you work it from there?
I don't know, I'm still confused. I'm really sorry about that. I don't really understand exactly what I'm meant to plug in and such.
You need to take what is given and use it to find what you can. Each step is a step towards the solution. First, look at the formula there: \(\measuredangle A = \dfrac{1}{2}\overset{\frown}{S}\). What can you use that and what is given to find?
110 = 1/2 S ??
Not quite. The arc is S. Since your problem already used S, I should have used some different letter... But this is what you can find: \(A=\dfrac{1}{2}110^\circ\) |dw:1401299418941:dw|
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