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OpenStudy (anonymous):

Algebra 1 Help: Finding Slope and Intercept, creating equations in slope-intercept form. (Problems #11, 17, 21, 23, 25, 29, 33.) - PICTURES INCLUDED

OpenStudy (anonymous):

OpenStudy (anonymous):

@marissalovescats @girlnotonfire @tayromo Do think you guys could help me?

OpenStudy (anonymous):

The slope form is y = mx + c So, compare the equation to find m (slope). The constant term is the intercept

OpenStudy (anonymous):

e.g. y = 3x + 4 means that the slope is 3 and the intercept is 4.

OpenStudy (anonymous):

if m = 1 and intercept = -1 then the equation is y = 1.x - 1 = x -1

OpenStudy (mathstudent55):

Here' help for #11. This is the slope-intercept form of the equation of a line. \(y = mx + b\) Where m = slope, and b = y-intercept. Once you have an equation in that form, just read off the slope and the intercept. For example, if the equation is \(y = \color{red}4x + \color{green}2\) The the \(slope = \color{red}{4}\), and the \(y-intercept = \color{green}{2}\)

OpenStudy (mathstudent55):

Problems 17 and 21 are the above procedure in reverse. For example, if the slope is 6 and the y-intercept is -4, then the equation is: y = 6x - 4

OpenStudy (mathstudent55):

The picture dosen't show 29 and 33.

OpenStudy (anonymous):

I'll post the picture for 25, 29 and 33 right now. Thank you both so very much!

OpenStudy (anonymous):

OpenStudy (anonymous):

Are you still there? I post the picture for 25, 29, and 33.

OpenStudy (anonymous):

What about 23 and 25?

OpenStudy (mathstudent55):

Problems 22 to 27 are done this way. You are shown a graph. From the graph you need to find the slope and the y-intercept. Then you just use the slope and the y-intercept to write the equation as y = mx + b

OpenStudy (mathstudent55):

The quicker thing to read off the graph is the y-intercept. To do that, just find the value at which the line crosses the y-axis.

OpenStudy (mathstudent55):

|dw:1401314493295:dw|

OpenStudy (mathstudent55):

For example, in the graph above, the y-intercept, b, is 3.

OpenStudy (mathstudent55):

The next thing you need to find is the slope.

OpenStudy (anonymous):

So for 23 would the y-intercept be -3?

OpenStudy (mathstudent55):

Correct.

OpenStudy (mathstudent55):

Now I'll tell you how to read the slope off a graph.

OpenStudy (anonymous):

Okay

OpenStudy (mathstudent55):

First, you must pick two points on the straight line. In theory, any two points will do, but in reality, this works best if the points are on an intersection of grid lines. This way you can read the points much more easily.

OpenStudy (mathstudent55):

Using problem 25 as an example, the point on the y-axis, (0, 4) is on the grid itself. Another point can be the point where the line crosses the x-axis. That point is (0, 2).

OpenStudy (mathstudent55):

Now that we have chosen two points, we need to find the slope.

OpenStudy (mathstudent55):

The slope is a ratio. A ratio is a comparison of numbers using division. The slope is the rise over the run. We divide how much we go up or down from one point to the other, by how much we go right or left from one point to the other.

OpenStudy (mathstudent55):

I'll draw it and explain it with the drawing.

OpenStudy (anonymous):

okay

OpenStudy (mathstudent55):

|dw:1401315415876:dw|

OpenStudy (mathstudent55):

We need to go from one point to the other. We can't go on the line. We are only allowed to walk vertically and horizontally.

OpenStudy (mathstudent55):

Let's say we start at the point where the line crosses the x-axis. |dw:1401315518138:dw|

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