can someone please help me learn how to graph quadratic equations? I WILL GIVE A MEDAL!!
you mean like parabolas
Jay - you are familiar with graphs already correct? x values go horizontzlly y values go vertically
yes I am pretty familiar with them, for the most part, yes. @wolf1728
Okay the reason I asked is what help do you need? If you were to plot y = x² + 4x -7 You just calculate the values for x from -10 to 10 and plot the y values for whatever the x values are
okay, so can you help me solve, y=-5x^+1 @wolf1728
That would be y = -5x² +1 right?
yea
So, I would calculate the y values for each x value of -10 to 10 If you have the software from Open Office (100% free) this would allow you to do this very quickly. Do you have Open Office?
probably not
It is WELL WORTH downloading because not only does it calculate values for you, it will also make a graph for you. (pretty useful huh?)
well yes, but I have a final tmrw, and I need to memorize the formula of the problem. it would be very helpful if u show me step-by-step yo.
Here are the figures from -10 to 10 -10 -499 -9 -404 -8 -319 -7 -244 -6 -179 -5 -124 -4 -79 -3 -44 -2 -19 -1 -4 0 1 1 -4 2 -19 3 -44 4 -79 5 -124 6 -179 7 -244 8 -319 9 -404 10 -499 If you were to graph this, it seems choosing the values x =-2 through x=2 would keep the graph reasonably small. Still I will attach the graph form x = -10 to x=10
okay, thanks wolf..
There is no "formula" to do this, but there are a few things to know. If the coefficient of x² is positive, graph is shaped like a 'U' If it is negative graph is shaped like this ∩
The roots of the quadratic equation will cross at the x axis: roots of this equation are -0.44721 and 0.44721 Redrawing the graph look at where the graph crosses the x axis.
okay..
Another graph
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