Question

log3(a-2)+log3(a-2)=2

Answer 1

it is log base of 3

Answer 2

\(\LARGE\color{blue}{ \bf log_3(a-2)+log_3(a-2)=2 }\)

\(\LARGE\color{blue}{ \bf log_3(a-2)^2=2 }\)

\(\LARGE\color{blue}{ \bf log_3(a-2)^2=2~log_33 }\)

\(\LARGE\color{blue}{ \bf log_3(a-2)^2=log_33^2 }\)

Answer 3

can you finish the problem ?

Answer 4

where did you get 2 log33

Answer 5

\[hint:~~~\log_aB=\log_aC~~~~~~there fore~~ B=C\]

log base 3 of 3 is a magic one :)

Answer 6

im not catching up, im sorry

Answer 7

I think I got it! just remembered this!
If y=b^x then log b y=x
thanks!