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Chemistry 22 Online
OpenStudy (anonymous):

Find the pH of the following solutions 36.45 g of HCl in 450.0 mL of water

OpenStudy (alphadxg):

assuming that the 36.45 was grams , then using molar mass.... find moles 36.45 gHCl @ 36.45 g/mol = 1mole of HCl find molarity: 1 moles HCl / .45L = 2.22 Molar of HCl which releases 100% of its ions = 2.22 Molar of H+ whose pH = .35 your answer is .35 pH

OpenStudy (alphadxg):

Cross check me, I didn't use a calculator used my pc. lol

OpenStudy (anonymous):

thank you

OpenStudy (alphadxg):

your welcome :)

OpenStudy (anonymous):

quick question how did you get the ph

OpenStudy (alphadxg):

for [H+] you do -log(Molarity) in this case, -log(2.22) @kir8686

OpenStudy (anonymous):

@alphadxg thank you again

OpenStudy (alphadxg):

Fan and medal if your question was answered :)

OpenStudy (anonymous):

@alphadxg do u mind if i ask you another similar question?

OpenStudy (alphadxg):

yea

OpenStudy (anonymous):

97.65 mg of NaOH in 375.0 mL of water

OpenStudy (alphadxg):

Well, look at the example we just did, only difference now is you have to convert 97.65 mg to grams, to do so we would just divide by 1000 to get grams. Then find the molar mass of Na, O, and H.

OpenStudy (alphadxg):

you try first.

OpenStudy (anonymous):

97.65/1000= .98?

OpenStudy (anonymous):

4.0 g of NaOH / 1 L

OpenStudy (anonymous):

molar mass of naoh is 39.997 g/mol

OpenStudy (alphadxg):

One key thing to point out here, to get pH you need to get your answer to be in Molarity (Moles / L)

OpenStudy (alphadxg):

97.65mg NaOH / 1000g = .098grams NaOH 375ml / 1000L = .375L To get molarity we would take .098grams NaOH / .375L = Molarity ok good, we are in molarity, to find pH we would take -log(Molarity) = pH

OpenStudy (anonymous):

.58

OpenStudy (alphadxg):

umm I'm getting 2.18

OpenStudy (anonymous):

.098/.375 i got .261333

OpenStudy (alphadxg):

|dw:1401343949615:dw|Ok these are the conversion you need to do first, next we need to get this to molarity (Moles / L) We have L, now to find Moles we have grams of NaOH, now we need to multiply by the mass to get it into moles. |dw:1401344064791:dw|Now all we have to do is find pH |dw:1401344203038:dw|

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