Question

quantum numbers for Fe (iron)
HELP

Answer 1

First write the electronic configuration for Fe atom....

Answer 2

1s2 2s2 2p6 3s2 3p6 4s2 3d6

Answer 3

YEP GOT THT

Answer 4

so, n=4, l=0,1,2,3, m=-3,-2,-1,0,1,2,3, s==1/2, -1/2

Answer 5

MY NUMBERS WERE : N=3, L=2, mL=-2,mN=-1/2

Answer 6

@Sourav12084 don't give direct answers, let she/he guys first.

Answer 7

oh looks like i am wrong

Answer 8

@alphadxg , I didn't give direct answers first..

Answer 9

oh yeah i thought because 3d orbital is last level that 3 equaled n

Answer 10

No, 4 is the last orbital...

Answer 11

o yep..ur ryte

Answer 12

and i did the orbital diagram as well

Answer 13

they want to know numbers for highest energy eleectron

Answer 14

hmm...nice work!

Answer 15

and i got -1/2

Answer 16

is that why yu have -1/2 as ms?....last arrow on orbital diagram points down ?

Answer 17

for the last 2 electrons, i.e, the valence shell electrons, the config will be:
n=4, l=0, m=0, s=+1/2
n=4,l=0,m=0,s=-1/2

Answer 18

why is l 0?

Answer 19

l is zero because, the value of l varies from 0 to n-1...in our case it is n=4, so l varies from 0,1,2,3....now 0 stands for s subshell, 1 for p, 2 for d, 3 for f....our last orbit is 4s...so n=4, l=0

Answer 20

ohhhhhhhh

Answer 21

so if n=5....then l would be 1?

Answer 22

if the electron is in 5p state, then it would be l=1...the value of l depends primarily on s,p,d,f...i.e, the subshell in which the electron is in...if it is 3p, then also it will be l=1...but if it 3s, then l=0...

Answer 23

ohhhhh i get it now thx

Answer 24

U r welcome...