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Chemistry 20 Online
OpenStudy (anonymous):

Help!!!!! Whos in Connexus chem!???

OpenStudy (alphadxg):

what can we help you out with?

OpenStudy (anonymous):

post the question buddy

OpenStudy (anonymous):

it not really a question i need help on doing the portfolios so i can get the credit

OpenStudy (anonymous):

u should post ur question, the one who knows will answered the question

OpenStudy (anonymous):

well i mean if you arent in connexus chem then you wouldnt know the question thats hy i asked so someone who has the portfolio could help

OpenStudy (anonymous):

i need help with the molar mass of a gas portfolio

OpenStudy (anonymous):

write question with data. then may be we will help u

OpenStudy (alphadxg):

You might as well ask the question..

OpenStudy (anonymous):

since the gas in your graduated cylinder is a mixture of butane and water vapor, you must determine the partial pressure of the butane, Pbutane, alone. To do this, consult a reference and record the partial pressure of the water vapor, Pwater a, at the temperature. Use the following formula to compute the partial pressure of the butane. Pbutane= Atmosphere - Pwater

OpenStudy (anonymous):

@aaronq

OpenStudy (alphadxg):

Quick question, is The total pressure of gases collected in the gas collection tube is equal to the atmospheric pressure in the laboratory?

OpenStudy (anonymous):

i believe so

OpenStudy (alphadxg):

Ptotal=P1+P2+P3 (this has to be for equilibrium) and that water molecules can cause a small amount of pressure as they escape from the liquid. This means(as given n the instructons) Ptotal= Pbutane+Pwater Ptotal is the pressure of the lab Pwater is the vapor pressure that water causes. you must have both these values. I'm assuming that you have the water temperature from somewhere, and you must also be given the atmospheric pressure as well. This means when you subtract Pwater from Ptotal, you get Pbutane.

OpenStudy (anonymous):

ohhhh it makes sense!!! :D thanks so much!!!!!!!!

OpenStudy (alphadxg):

I thought I was going to have to explain more, guess not haha. :)

OpenStudy (anonymous):

i was just semi lost lol i got most of it just was missing a breakdown formula

OpenStudy (alphadxg):

lol no problem.

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