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What is the fourth term in this multiplication pattern? 2 x 6 n-1
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\[2^{n-1}\]
put n=4
@Shay17
yes substitute 4 for n
is that you get 432
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47
A. 12 B. 72 C. 432 D. 2592
6 times 2 = 12 12 times 4 = 48 48 minus 1 = 47
Go with C. then
idk I got what u got shay this question is weird
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idk how @matricked got 432 because he didn't explain , the #1 thing you're supposed to do
yeah @matricked
2*6^(4-1) =2*6^3=2*216=432
ohh well that makes sense if it was an exponent then
ill just go with C and hope for the best
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@Lindsay_552 please use the carrot symbol "^" if there is an exponent in your problem
C is correct @Lindsay_552
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