Question

It's an aptitude question:
Take five 3's and use any mathematical operation.
your answer should be 31?

Answer 1

Are you limited to using only one type of mathematical operation?

Answer 2

no, you can use any mathematical operation between two 3's

Answer 3

\[3 + 3 + 3 + 3 + 3 = 15 \]

\[3 - 3 - 3 - 3 - 3 - 3 = -15 \]

\[3 \times 3 \times 3 \times 3 \times3 = 243 \]

\[3\div3\div3\div3\div3\div3 = 0.01234567901 \]

Do these follow the rules?

Answer 4

no but instead you can use 3+3-3*3/3
any mathematical operation between any two 3's

Answer 5

Mhm ok

Answer 6

3^5/x=31

Answer 7

@dan815 use 3's

Answer 8

5/log 3 base 31 =x

Answer 9

you have to use only five 3's,not less than that and not more than that

Answer 10

(3*3*3*3*3)^(5/5/log 3 base 31)

Answer 11

:p

Answer 12

thats an operation on 5 3s

Answer 13

but you used 5 and base 31

Answer 14

why cant that be an operation!!

Answer 15

fine ill do it properly!

Answer 16

how about 3^0 is that allowed

Answer 17

no 3^3 is allowed

Answer 18

operand should only be 3,operations can be any mathematical operations

Answer 19

\(\huge 3^3 + \dfrac{3}{3} +3 \)

Answer 20

3^3+3+3/3

Answer 21

NO :(

Answer 22

thought process:

3^3 =27

how do i get 3 using 3 threes

how do i get 1 using 2 3s

simple

Answer 23

foiled by hatnn

Answer 24

yes you had to have known u need a 1 no matter what because, 31 is not a factor of 3

Answer 25

thanks @hartnn and @dan815

Answer 26

Hartnn too gewd c;

Answer 27

***how do i get 4 using 3 threes

Answer 28

guys,
try 40
using 5 threes.

Answer 29

@ShadowLegendX @dan815

Answer 30

3+3/3=4 @hartnn

Answer 31

oh i asked 40
not 4
that too using 5 threes, not more, not less