Question

Help please!
Given that the area of B=5, Integral of (-2,1) f(x) dx=2, and integral of (1,8) f(x)dx= -4, find:
1) Integral of (6,8) f(x) dx
2) Integral of (-2,8) {absolute value of f(x) }dx

Answer 1

Do you have a picture of B anywhere?

Answer 2

no, I wasn't given that :/

Answer 3

Well I don't think (a) or (b) is doable unless you have some more information about \(f(x)\)...

Answer 4

no that's all I have, but how about these other exercises, will they be doable?
1) integral of (-2,6) f(x) dx
2) integral of (-2,8) f(x) dx
3) integral of (1,6) f(x) dx ? With the same info as above?

Answer 5

The second one definitely is, but for the other two we need to know one of the following areas:
\[\int_6^\cdots f(x)~dx~~\text{or}~~\int_\cdots^6f(x)~dx\]

Answer 6

Whatever those may be,
\[\int_{-2}^8f(x)~dx=\int_{-2}^1f(x)~dx+\int_1^8f(x)~dx\]

Answer 7

Seeing as you're expected to find
\[\int_{-2}^6 f(x)~dx~~\text{and}~~\int_1^6f(x)~dx~~\text{and}~~\int_6^8f(x)~dx\]
I'm willing to bet that "the area of \(B=5\)" has something to with it. There must be a picture for this problem.

Answer 8

No picture was given unfortunately, that is why I was a little confused when doing this problem ( which I got all wrong).

Answer 9

No other info about \(B\)?

Answer 10

no