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OpenStudy (luigi0210):
Distribute
OpenStudy (luigi0210):
It should give you a trig identity ~
OpenStudy (johnweldon1993):
Looks like a difference of squares
\[\large (1 - sin(x))(1 + sin(x))\]
distribute that out
random231 (random231):
(a + b)(a-b)=A^2 - b^2
OpenStudy (anonymous):
tan2 x ?
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OpenStudy (johnweldon1993):
Not quite...
\[\large (1 - sin(x))(1 + sin(x))\]
When you distribute that out you should have gotten
\[\large 1 -sin(x) + sin(x) - sin^2(x))\]
did you get that?
OpenStudy (anonymous):
no
OpenStudy (anonymous):
1
cos2 x
sin2 x
tan2 x
OpenStudy (johnweldon1993):
Yes, because when you foil (distribute) that out...you do
|dw:1401474511633:dw|
OpenStudy (johnweldon1993):
so since we have that...we can simplify it a bit...
\[\large 1 \cancel{- sin(x) + sin(x)} - sin^2(x)\]
whch leaves us with
\[\large 1 - sin^2(x)\]
You should have seen this before via a trig identity
Hint* \[\large sin^2(x) + cos^2(x) = 1\]
based on that...what will your answer be?
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OpenStudy (anonymous):
is the answer 1?
random231 (random231):
no! its an easy problem. i recommend you work out the sum again on a piece of paper.
OpenStudy (anonymous):
cos2 x
OpenStudy (johnweldon1993):
Correct!
OpenStudy (anonymous):
thank you do you mind helping with a couple more just 2
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OpenStudy (anonymous):
johnweldon1993 thank you do you mind helping with a couple more just 2