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Mathematics 20 Online
OpenStudy (anonymous):

Simplify (1 − sin x)(1 + sin x).

OpenStudy (luigi0210):

Distribute

OpenStudy (luigi0210):

It should give you a trig identity ~

OpenStudy (johnweldon1993):

Looks like a difference of squares \[\large (1 - sin(x))(1 + sin(x))\] distribute that out

random231 (random231):

(a + b)(a-b)=A^2 - b^2

OpenStudy (anonymous):

tan2 x ?

OpenStudy (johnweldon1993):

Not quite... \[\large (1 - sin(x))(1 + sin(x))\] When you distribute that out you should have gotten \[\large 1 -sin(x) + sin(x) - sin^2(x))\] did you get that?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

1 cos2 x sin2 x tan2 x

OpenStudy (johnweldon1993):

Yes, because when you foil (distribute) that out...you do |dw:1401474511633:dw|

OpenStudy (johnweldon1993):

so since we have that...we can simplify it a bit... \[\large 1 \cancel{- sin(x) + sin(x)} - sin^2(x)\] whch leaves us with \[\large 1 - sin^2(x)\] You should have seen this before via a trig identity Hint* \[\large sin^2(x) + cos^2(x) = 1\] based on that...what will your answer be?

OpenStudy (anonymous):

is the answer 1?

random231 (random231):

no! its an easy problem. i recommend you work out the sum again on a piece of paper.

OpenStudy (anonymous):

cos2 x

OpenStudy (johnweldon1993):

Correct!

OpenStudy (anonymous):

thank you do you mind helping with a couple more just 2

OpenStudy (anonymous):

johnweldon1993 thank you do you mind helping with a couple more just 2

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