I give medal and fan Which best describes the spread of a set of data that has an interquartile range of 12 and a mean absolute deviation of 8? A. The average distance of all data values from the mean is 12 and the middle 50% of data values has a range of 8. B. The average distance of all data values from the mean is 8 and the middle 50% of data values has a range of 12. C. The average distance of all data values from the mean is 10 and the middle 50% of data values has a range of 4. D. The average distance of all data values from the mean is 10 and the middle 50% of data values has a range of 20.
@Kittykitty1963
I have no idea man.
ok
@Embryo
can u figure it out
IQR, or interquartile range, is calculated as follows,\[Q_3-Q_1=IQR\]\[Q_3\]is calculated to be the value where 75% of the data is below it, Q_1 is determined to be the point at which 25% of the date are below it, having a mean of 8 means that it's the average number, where 50% of the data are above and below that number
Standard deviance is just how far away from the average you get
so b?
Okay, now with all that information, to answer your question, notice, that\[IQR=Q_3-Q_1\]gives you the range of the middle 50%
Yes! great job
ok thx
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