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Mathematics 15 Online
OpenStudy (anonymous):

I give medal and fan Which best describes the spread of a set of data that has an interquartile range of 12 and a mean absolute deviation of 8? A. The average distance of all data values from the mean is 12 and the middle 50% of data values has a range of 8. B. The average distance of all data values from the mean is 8 and the middle 50% of data values has a range of 12. C. The average distance of all data values from the mean is 10 and the middle 50% of data values has a range of 4. D. The average distance of all data values from the mean is 10 and the middle 50% of data values has a range of 20.

OpenStudy (anonymous):

@Kittykitty1963

OpenStudy (anonymous):

I have no idea man.

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

@Embryo

OpenStudy (anonymous):

can u figure it out

OpenStudy (anonymous):

IQR, or interquartile range, is calculated as follows,\[Q_3-Q_1=IQR\]\[Q_3\]is calculated to be the value where 75% of the data is below it, Q_1 is determined to be the point at which 25% of the date are below it, having a mean of 8 means that it's the average number, where 50% of the data are above and below that number

OpenStudy (anonymous):

Standard deviance is just how far away from the average you get

OpenStudy (anonymous):

so b?

OpenStudy (anonymous):

Okay, now with all that information, to answer your question, notice, that\[IQR=Q_3-Q_1\]gives you the range of the middle 50%

OpenStudy (anonymous):

Yes! great job

OpenStudy (anonymous):

ok thx

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