Eliminate the parameter of x =1/2 t, y=((3t)^3) -1

Question

loser66 · Answer

Your avatar is so cute!!

loser66 · Answer

$$x =\dfrac{t}{2}\rightarrow t=??$$

anonymous · Answer

Thanks! And are you asking for clarification of the problem or is that the first step to solving it?

loser66 · Answer

That is the first step

anonymous · Answer

But x is equal to 1/2 not t/2?

loser66 · Answer

1/2 t is 1/2*t = t/2 hun

anonymous · Answer

K but my equation looks like this: http://imgur.com/NM4EDJc I think I wrote it out wrong...

loser66 · Answer

You are good, just find t  and then plug t into y 
Ok, I do it for you. 
$$x =\frac{t}{2}\rightarrow t = 2x$$
$$y =(3t)^3 -1$$ replace t =2x above into y
$$y =(3(2x))^3 -1 =(6x)^3 -1=216x^3 -1$$
no more t, right? That's the process to "Eliminate t"

anonymous · Answer

Sorry, i had to step out to talk to my teacher. That makes a lot of sense (and now i feel really stupid) whats the next step?

loser66 · Answer

the next step is "submit"

anonymous · Answer

I don't have your answer exactly but I have y = 6x^3 - 1? 6 is the cube root of 216 so would that work?

anonymous · Answer

Thanks so much for all your help! <3