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Mathematics 13 Online
OpenStudy (anonymous):

please help

OpenStudy (anonymous):

ahh okay, so did you simplify the expression that included the "a"s in it? Just say you if you did, and you can post your answer of you want and i can check it

OpenStudy (anonymous):

Nope, okay, so you have to look at this as if "a" is a variable, once you simplify the side of the function with the "a" you should get this\[8x^4-2ax^3+4x^2-20ax^2-10=\]now it tells you what the simplest form of that equation with "a"s is, which means\[8x^4-2ax^3+4x^2-20ax^2-10=8x^4-6x^3-56x^2-10\]now notice something, you can simplify, since both sides have a few of the same terms,\[-2ax^3+4x^2-20ax^2=-6x^3-56x^2\]all that's left to do is figure out those pesky "a"s

OpenStudy (anonymous):

we can solve for those "a"s by doing a little trick, notice that we can set the parts with equivalent x's as equal to each other, so\[-2ax^3=-6x^3\]and then\[4x^2-20ax^2=-56x^2\]and you should be able to solve those, take note that you should get the same "a" for both

OpenStudy (anonymous):

Dang, you beat me to it, Yes! you're correct again

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