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Can anyone solve this? 675.54=P(1+0.025/2)^2(11)?
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OpenStudy (anonymous):
Like this? \[675.54=p(1+0.025/2)^{2(11)}\]
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
Exactly like this?
OpenStudy (anonymous):
yes sir
OpenStudy (anonymous):
You need to solve for p I assume?
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OpenStudy (anonymous):
i believe so
OpenStudy (anonymous):
Well we need to isolate p to one side of the equation. Any thoughts on how?
OpenStudy (anonymous):
no idea
OpenStudy (anonymous):
8 = 4x. If I divide both sides by 4 what do I end up with?
OpenStudy (anonymous):
2x
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OpenStudy (anonymous):
2=x correct
OpenStudy (anonymous):
So if I divide both sides of you equation by the following..what do you end up with?\[(1+0.025/2)^{2(11)}\]
OpenStudy (anonymous):
(1+0.025/2)^2(11)
(1.0125)^2(11)?
OpenStudy (anonymous):
(1.0125)^22?
OpenStudy (anonymous):
That's one step ahead of me. I f we divide both sides of the equation y (1+0.025/2)2^(11)..we would end up with \[\frac{ 675 }{ (1+0.025/2)^{2(11)} } = p\]
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OpenStudy (anonymous):
Do you see how I did that?
OpenStudy (anonymous):
okay then what?
OpenStudy (anonymous):
Solve the equation. First solve for (1.0125) ^22....then divide that into 675 and there is your answer for p.
OpenStudy (anonymous):
this is what i get for (1.0125)^22=1.3142884808187545
OpenStudy (anonymous):
@nelsonjedi ?
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