please help
The way to do this is easy from what i've seen that you know how to do, you're a freaking genius afterall, so, first things first, factor that equation like you did on the last one i helped you with when you were finding the axis of symmetry
Of course you are, but go ahead and complete the square for this one again, and make it look something like\[y=a(x-h)^2+k\]
The problem is that it's neither of those, let me work step by step here so you can see where you went wrong
\[3x^2-12x+3=3(x^2-4x)+3\]so from here we complete the square adding a 4 to the inside of the parenthesis, and we subtract a 3 that needs to be multiplied by that 3 on the outside of the parenthesis so we get\[3(x^2-4x+4)+3-12\]after simplifying and factoring the parenthesis, since now it's a perfect square we get\[y=3(x-2)^2-9\]
Looking at the work you typed up, you took the derivative? if so you took the derivative of\[3x^2\]wrong, as it should have been 6x, not -6x
Before your break lets finish this question haha, from that answer you know the vertex now right? it should be\[(h,k)\]as seen in the general formula, just match up the parts
If you understand how to get the correct answer of c) then i hope you enjoy your break :) and i hope you have a wonderful night since it's getting quite late here for me (9pm) being late
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