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Mathematics 21 Online
OpenStudy (anonymous):

please help

OpenStudy (anonymous):

The way to do this is easy from what i've seen that you know how to do, you're a freaking genius afterall, so, first things first, factor that equation like you did on the last one i helped you with when you were finding the axis of symmetry

OpenStudy (anonymous):

Of course you are, but go ahead and complete the square for this one again, and make it look something like\[y=a(x-h)^2+k\]

OpenStudy (anonymous):

The problem is that it's neither of those, let me work step by step here so you can see where you went wrong

OpenStudy (anonymous):

\[3x^2-12x+3=3(x^2-4x)+3\]so from here we complete the square adding a 4 to the inside of the parenthesis, and we subtract a 3 that needs to be multiplied by that 3 on the outside of the parenthesis so we get\[3(x^2-4x+4)+3-12\]after simplifying and factoring the parenthesis, since now it's a perfect square we get\[y=3(x-2)^2-9\]

OpenStudy (anonymous):

Looking at the work you typed up, you took the derivative? if so you took the derivative of\[3x^2\]wrong, as it should have been 6x, not -6x

OpenStudy (anonymous):

Before your break lets finish this question haha, from that answer you know the vertex now right? it should be\[(h,k)\]as seen in the general formula, just match up the parts

OpenStudy (anonymous):

If you understand how to get the correct answer of c) then i hope you enjoy your break :) and i hope you have a wonderful night since it's getting quite late here for me (9pm) being late

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