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A can contains 14 pennies, 12 nickles, 16 dimes, and 8 quarters. What is the probability of drawing either a penny or a nickle on one draw?
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The events 'draw a penny' and 'draw a nickle' are mutually exclusive. Therefore we can find the probability of drawing either a penny or a nickle on one draw by adding the probabilities of 'draw a penny' and 'draw a nickle'. \[P(draw\ a\ penny)=\frac{14}{50}\] \[P(draw\ a\ nickle)=\frac{12}{50}\] Can you finish the calculation now?
@_Michaeld22
\[\frac{14}{50}+\frac{12}{50}=\ ?\]
13/25
You are correct!
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