help!
simplify \[\sqrt{140}\]
Alrighty, do you know what you can multiply to get 140?
lol 70 and 2
alrighty, so now you have this\[\sqrt{140}=\sqrt{2*70}\]break it down further, what are multiples of 70?
7 and 10
and multiples of 10 are 2 and 5
alrighty, since you used those multiples, we need to break it down one more time, since we have\[\sqrt{140}=\sqrt{70*2}=\sqrt{7*10*2}\]
there you go, now you understand so
now we have this\[\sqrt{140}=\sqrt{2*2*5*7}=\sqrt{2}*\sqrt{2}*\sqrt{5}*\sqrt{7}\]so do you know what happens when you multiply\[\sqrt{2}*\sqrt{2}\]
\[\sqrt{4}\]
yup, and what does that simplify to?
2
Bam, so now look what we have,\[2*\sqrt{7}*\sqrt{5}=2\sqrt{35}\]sadly that's as far as you can simplify this, so you're done once you get that far
yay thanks ! now what about this? what is the simplified form of \[\sqrt{48n^9}\]
that is a 9
n to the power of 9 right?
yes
Alrighty, so here are some rules for you to remember that will help, when asked to simplify a square root, try to take the regular number, and break it down to numbers that are perfect squares, so 48 should be broken down like this\[\sqrt{48}=\sqrt{4*12}=\sqrt{4*4*3}\]so you can simplify that, and here's the next rule\[n^9=n^4*n^4*n\]why is this true? because\[x^{a+b}=x^a*x^b\]so you can break up the power
ok so the answer would be\[4n^4 \sqrt{3n}\]
Great job! Yes, that's correct
:) thanks
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