10 mL of 1.10M sodium hydroxide titrant was required to reach the equivalence point when titrating a 50mL sample of dilute sulfuric acid what was the concentration of the acid?

Question

anonymous · Answer

the answer is 0.010M if that helps

somy · Answer

can u write a balance equation for this reaction between NaOH and H2SO4?

somy · Answer

balanced*

somy · Answer

im getting 0.11 M for con of H2SO4

anonymous · Answer

2NaOH+H2SO4= NaSO4+2H2O

somy · Answer

owh thats wrong

somy · Answer

oxidation state of Na is +1 and for SO4 its -2

somy · Answer

so that will be  $$Na _{2}SO _{4}$$

somy · Answer

$$2NaOH + H _{2}SO _{4} \rightarrow Na _{2}SO _{4} + 2H _{2}O$$

somy · Answer

now that u know the equation 
for NaOH you are given volume and molarity 
so use your values in formula 
$$molarity = mole \div dm ^{3}$$ 
to find mole of NaOH, convert mL which is basically cm3 to dm3 by dividing given volume by 1000

somy · Answer

get it so far?