Mg(s) +CuO(s) -- MgO(s) +Cu(s)
explain the redox reaction fully, stating clearly which is oxidised and which is reduced

Ans: Mg reduces Cu by giving 2 electrons to Cu
Mg is oxidised
Oxidation number of Mg increases from 0 to +2
Cu oxidised Mg by gaining 2 electrons from Mg
Cu is reduced
Oxidation number of Cu decreases from +2 to 0
total number of electrons gained or lost is 2

is this correct??

Question

Mg(s) +CuO(s) --> MgO(s) +Cu(s)
explain the redox reaction fully, stating clearly which is oxidised and which is reduced

Ans: Mg reduces Cu by giving 2 electrons to Cu
        Mg is oxidised
       Oxidation number of Mg increases from 0 to +2
        Cu oxidised Mg by gaining 2 electrons from Mg
        Cu is reduced
      Oxidation number of Cu decreases from +2 to 0
total number of electrons gained or lost is 2
  
is this correct??

anonymous · Answer

yes perfect!