Question

The figure shows triangle ABC with medians AF, BD, and CE. Segment AF is extended to H in such a way that segment GH is congruent to segment AG:

Answer 1

Which conclusion can be made based on the given conditions?

Segment EG is congruent to segment GD.

Segment GF is half the length of segment EB.

Segment BG is congruent to segment GC.

Segment EG is half the length of segment BH.

Answer 2

@mathslover can you help me please?

Answer 3

I think, its D.

Answer 4

It is clear that AG = GH (given.)

In triangle ABH :

G is mid point of AH
E is mid point of AB

Answer 5

Thus, using mid-point theorem,

\(\boxed{EG = \cfrac{BH}{2}}\)

Answer 6

Thank you for the help! Sorry I did not respond I had to go do chores and thank you again I am so terrible at math I need all the help I can get

Answer 7

Could you help me with a few more questions?

Answer 8

If triangle ABC is congruent to triangle DEF, which statement is not true?
segment AB ≅ segment DE

Answer 9

∠C ≅ ∠E

segment BC ≅ segment EF

∠A ≅ ∠D

Answer 10

Parallelogram ABCD is similar to parallelogram EFGH. Angle A is congruent to the measure of angle ___.
E

F

G

H