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u may use the geometry : integral between x=-r to r is same as the area of circle \(\pi r^2\)
x = (-5 + 4) / 2 x = -1/2 y = (1 - 8) / 2 y = -7/2 center is (-1/2, -7/2) (x - (-1/2))^2 + (y - (-7/2))^2 = r^2 (x + 1/2)^2 + (y + 7/2)^2 = r^2 find the distance of the diameter and divide by 2 for the radius d = √[(-5 - 4)^2 + (1 - (-8))^2] d = √(81 + 81) d = √162 d = 9√2 r = 9√2/2 r^2 = 162/4 r^2 = 81/2 (x + 1/2)^ + (y + 7/2)^2 = 81/2
how would you integrate (x + 1/2)^ + (y + 7/2)^2 = 81/2 ?
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