Using the following equation, find the center and radius of the circle. You must show all work and calculations to receive credit. x2 + 4x + y2 - 6y = -4 (8 points)
Can someone please help me
\(\LARGE\color{black}{ \bf x^2 + 4x + y^2 - 6y = -4}\) \(\LARGE\color{black}{ \bf x^2 + 4x\color{red} { +4 } + y^2 - 6y\color{blue} { +9 } = -4\color{red} { +4}\color{blue} { +9 } }\)
Can you finish the problem off, knowing that the equation of the circle looks like, \(\LARGE\color{black}{ \bf (x-h)^2+(y-k)^2=r^2}\)
Where (h,k) is the center, and r is the radius.
I am giving one more hint. \(\LARGE\color{red}{ \bf x^2+4x+4}\) and \(\LARGE\color{blue}{ \bf y^2-6y+9}\) are both perfect squares.
*trinomials
I think i have the center correct but im a little confused on finding the radius @SolomonZelman @acxbox22
Oh never mind i got it now
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