Question

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Answer 1

Dominick is planning to take a vacation to either Orlando or Tampa Bay. He wants to go to the city that is warmer, on average. The box plot below shows the temperatures from the previous year during the time that Dominick will take his vacation:


Which city should Dominick visit, and why?

He should visit Orlando. It has a greater IQR.

He should visit Orlando. The median is higher and the range is smaller, so the temperature is higher on average.

He should visit Tampa Bay. The highest temperature occurred there.

He should visit Tampa Bay. The range is very large, so there is a better chance that any given day will be warm.

Answer 2

He should visit Orlando. The median is higher and the range is smaller, so the temperature is higher on average.

This is the correct answer, as we are only interested in the average temperature in both cities in deciding which to go to. The larger the range (max - min values) or interquartile range (range of central box), the more spread out the temperatures are around the median. As Orlando's range and interquartile range is lower than Tampa Bay's, and its median (middle value in the data set of temperatures) is higher, Dominick would, on average, have more chance of visiting Orlando on a day when it was warmer than Tampa Bay than the other way around.

Answer 3

Thank You! @Ciarán95 I appreciate it :)

Answer 4

Which of the following is true of the data set represented by the box plot?

box plot with min at 10.5, Q1 at 11.5, median at 12.5, Q3 at 13.5, max at 15

The data contains at least one outlier.

The mean and median are most likely the same or very close.

The data is skewed to the right.

The median is 11. -- this is wrong.

Points earned on this question: 0




Question 2 (Worth 1 points)

[06.03]

The data set shows the test scores for 7 students in a math class:



Amit
88

Traci
76

Lee
54

Barry
83

Amy
92

Ling
95

Rachael
80

When calculating the average score for the class, the teacher claims that she should exclude Lee's test score because he was absent the entire week before the test.

Evaluate this claim by selecting the statement that best reflects why the reasoning is either correct or flawed.
The reasoning is flawed. Lee's test score is not an outlier and removing it would decrease the mean.

The reasoning is correct. Lee's test score is an outlier and excluding it would increase the mean.

The reasoning is flawed. Lee's test score is an outlier, but there is no evidence that this test score is not typical. -- wrong

The reasoning is correct. Lee's test score is not an outlier, but the value should not be included anyway due to the fact that he was absent.

Points earned on this question: 0




Question 3 (Worth 2 points)

[06.03]

If the outliers are not included, what is the mean of the data set?

76, 79, 80, 82, 50, 78, 83, 79, 81, 82

77

78

79

80 --- right

Points earned on this question: 2




Question 4 (Worth 2 points)

[06.03]

Dominick is planning to take a vacation to either Orlando or Tampa Bay. He wants to go to the city that is warmer, on average. The box plot below shows the temperatures from the previous year during the time that Dominick will take his vacation:

box plot labeled Orlando with min at 64.5, Q1 at 65.5, median at 67.5, Q3 at 71.5, max at 72.5. Box plot labeled Tampa Bay with min at 60, Q1 at 63.5, median at 66.25, Q3 at 72.5, max at 74

Which city should Dominick visit, and why?

He should visit Orlando. It has a greater IQR.

He should visit Orlando. The median is higher and the range is smaller, so the temperature is higher on average. -- right

He should visit Tampa Bay. The highest temperature occurred there.

He should visit Tampa Bay. The range is very large, so there is a better chance that any given day will be warm.

Points earned on this question: 2




Question 5 (Worth 1 points)

[06.03]

Given the box plot, will the mean or the median provide a better description of the center?

box plot with min at 6, Q1 at 7.5, median at 8, Q3 at 23, max at 32.5

The mean, because the data distribution is symmetrical

The median, because the data distribution is symmetrical

The mean, because the data distribution is skewed to the right

The median, because the data distribution is skewed to the right -- right

Points earned on this question: 1




Question 6 (Worth 2 points)

[06.03]

When the outliers are removed, how does the mean change?

dot plot with 1 on 50, 1 on 76, 1 on 78, 2 on 79, 1 on 80, 1 on 81, 2 on 82, 1 on 83

The mean decreases by 3.

The mean increases by 2.

The mean increases by 3. -- right

There are no outliers.

Points earned on this question: 2