Question

Algebra simplification problem

Answer 1

whats your problem

Answer 2

I cannot see where the 1- is coming from simplification.

Answer 3

@jjuden ^^

Answer 4

\[Q_0= Q_1+JA\rightarrow J= \dfrac{Q_0-Q_1}{A}\]
got this part?

Answer 5

yep

Answer 6

\[Q_0c_0 =Q_1c_1\rightarrow Q_1=\dfrac{Q_0c_0}{c_1}\]got this part?

Answer 7

knock knock... are you sleeping?

Answer 8

Sorry, website is lagging for me. I got ya.

Answer 9

so, just plug Q1 into the previous one, you have
\[J= \dfrac{Q_0-\dfrac{Q_0c_0}{c_1}}{A}\]

Answer 10

Then just divide?

Answer 11

by Q0

Answer 12

I mean bring q0 outside the bracket and divide

Answer 13

simplify it \[J = \dfrac{Q_0}{A}-\dfrac{Q_0c_0}{Ac_1}\]
factor \(\dfrac{Q_0}{A}\) out

Answer 14

you get what you don't know
\[J= \dfrac{Q_0}{A}(1-\dfrac{c_0}{c_1})\]

Answer 15

Is it clear?

Answer 16

Yeah, makes perfect sense. Thank you!

Answer 17

np