Find the vertex of the parabola whose equation is y = x^2 + 6x + 2. What is the line of symmetry for the parabola whose equation is y = 3x^2 + 24x - 1? What is the line of symmetry for the parabola whose equation is y = x^2 + 10x + 25? Find the vertex of the parabola whose equation is y = -2x^2 + 8x - 5. What is the line of symmetry for the parabola whose equation is y = x^2 - 12x + 7? Find the vertex of the parabola whose equation is y = x^2 - 4x + 6.
@satellite73
What is the line of symmetry for the parabola whose equation is y = x^2 + 10x + 25?
\(-\frac{b}{2a}=-\frac{10}{2\times 1}=-5\) is what you are looking for
line is \(x=-5\)
we havent done the first one yet silly! ;] @satellite73
Find the vertex of the parabola whose equation is \(y = -2x^2 + 8x - 5\) first coordinate of the vertex is \(-\frac{b}{2a}=-\frac{8}{2\times (-2)}=2\)
oh well lets finish this one first coordinate of the vertex is \(2\) second coordinate of the vertex is what you get when you replace \(x\) by \(2\) namely \[-2(2)^2+8\times 2-5=3\] vertex is \[(2,3)\]
can you fan me so i can message you
k
Find the vertex of the parabola whose equation is \(y = x^2 + 6x + 2\) what is \(-\frac{b}{2a}\) in this case? hint: \(a=1,b=6\)
you got this? or you still need help with it?
hm, so c is 2?
yes, \(c=2\) but you don't use \(c\) to compute the first coordinate of the vertex it is \[-\frac{b}{2a}\]
for question one it is \[-\frac{6}{2\times (1)}=-3\]
so 6/2 = 3
don't forget the minus sign
oh and the negative
what about the other one?
right now you have to find the second coordinate of the vertex \[y = x^2 + 6x + 2. \] and replace \(x\) by \(-3\) using parentheses gives you \[y=(-3)^2+6\times (-3)+2=9-18+2=-9+2=-7\]
that makes the vertex \((-3,-7)\)
what is the next one we need to do?
wow, youre so quick. the next one is What is the line of symmetry for the parabola whose equation is y = 3x^2 + 24x - 1?
i think the answer is -8 but im not sure
once again it is \(-\frac{b}{2a}\) which in this case is \[-\frac{24}{2\times (3)}=-\frac{24}{6}\]
so the answer is -4
so no, it is not \(-8\)
yes
since it is a line, the answer is actually \(x=-4\)
what next?
What is the line of symmetry for the parabola whose equation is y = x2 - 12x + 7?
this one is for you to try first again it is \(-\frac{b}{2a}\) this time with \(a=1,b=-12\)
so its 12/2
yes better known as \(6\) but yes also don't forget it is \(x=6\) the vertical line
that it, or is there more?
ill make a new post
k
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