Find the vertex of the parabola whose equation is y = x^2 - 4x + 6. Find the y-coordinate of the vertex of the parabola whose equation is y = x^2 - x + 2.
and once again, \[-\frac{b}{2a}\]
\[ y = x^2 - 4x + 6\] \[a=1,b=-4\]
let me know what you get
you could always go full derp and use a graphing calculator but it is far easier to just use the formula
4/2 which is 2?
yes, right that is the first coordinate of the vertex
whats the equation for the second coordinate?
second coordinate is \[ y = 2^2 - 4\times 2 + 6\]
i.e. what you get for \(y\) when you replace \(x\) by the first coordinate
in this case it is \(y=4-8+6=-4+6=2\) so both the first and second coordinate of the vertex is \(2\) and the vertex is \((2,2)\)
is the y coordinate the first or second one in the parentheses?
Find the y-coordinate of the vertex of the parabola whose equation is \(y = x^2 - x + 2\) is a bit trickier because you have to work with fractions
the \(y\) coordinate is the second one it goes \((x,y)\)
easy enough to remember because \(x\) comes before \(y\) in the alphabet
ah, then i think the answer is 1 and 3/4
for \[y=x^2-x+2\]?
oh wait wait wait, is it 2 and 1/4?
not quite
2? -.-
it is still \[-\frac{b}{2a}\] but in this case \(a=1,b=-1\) so the first coordinate of the vertex is \(\frac{1}{2}\) not \(2\) you had it upside down
the second coordinate takes some arithmetic it is \[y=\left(\frac{1}{2}\right)^2-\frac{1}{2}+2\]
which, if my arithmetic is correct, is \[\frac{1}{4}-\frac{1}{2}+2=-\frac{1}{4}+2=\frac{7}{4}\]
wanna check it?
which is 1 and 3/4!
i knew that was the right answer!
hold the phone it is \((\frac{1}{2},\frac{7}{4})\) which is not \((1,\frac{3}{4})\)
clear?
no, 7/4 = 1 and 3/4
i only need the y
right dad?
ooh i see what you are saying!!
yes dear now don't stay out too late
lol! i wont, im just going to get pellet faced and be a whore!
lol
you done? or are there more
ill make a new post, and omg thanks for helping me so much dad!
yw dear
Join our real-time social learning platform and learn together with your friends!