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Mathematics 23 Online
OpenStudy (anonymous):

I have an exam coming up tomorrow. Please help. Find the degree of the the polynomial: g(x) = (2x+1)(x-4)^3

OpenStudy (anonymous):

I think the answer is 3 but I am not sure if I have to foil it.

OpenStudy (anonymous):

no not 3

OpenStudy (anonymous):

the degree of \((x-4)^3\) is 3, but you have another \(x\) term out front

OpenStudy (anonymous):

yes, so there is an x^1 and degree of 3 so would I add it to 4?

OpenStudy (anonymous):

@satellite73

OpenStudy (kainui):

Yeah, the degree of the polynomial is based off looking at it when it's in this form something like this, here this is just an arbitrary degree 5 polynomial. \[f(x)=Ax^5+Bx^4+Cx^3+Dx^2+Ex+F\] So basically what you need to do is multiply it out. Although along the way you might notice that there's a faster way to recognizing what it will eventually turn out to be without having the multiply it.

OpenStudy (anonymous):

OK, so I would multiply it out to (x-4)(x-4)(x-4)(2x+1)... there is got to be a faster way to multiply that out or I would be taking a lot of time on the test

OpenStudy (anonymous):

@Kainui

OpenStudy (kainui):

Yes, there is a faster way, but you'll discover it when you start multiplying it out. What do you think it'll turn out to be a degree of by just looking at it? Remember, the highest degree will be the term with all the x's in it.

OpenStudy (anonymous):

I can see that the highest degree without multiplying it out is 3

OpenStudy (kainui):

Nope, sorry.

OpenStudy (anonymous):

Actually, the coefficient 2x has a 1 so the highest should be 4

OpenStudy (kainui):

Wait, what do you mean?

OpenStudy (kainui):

The highest order term is 4, but I don't think how you go there was correct.

OpenStudy (anonymous):

Let me see if I can try to explain what I mean

OpenStudy (anonymous):

I see that there is a (2x+1) and a (x-4)^3 so the 2x has a degree of 1 and the x-4 has a degree of 3

OpenStudy (anonymous):

That is where I came up with 4

OpenStudy (anonymous):

I want to get there without having to multiply it all out

OpenStudy (kainui):

Yeah exactly, that's the correct explanation. Good. Yeah, the main thing is that I know you want to get the "quick" way but since you're not on the test it helps to do it the long way now. That way you understand where the quick method comes from, if that makes sense. Now is when you have the extra time to understand it so that on the test you can sort of do it more in your mind because you've been there and know what will happen. Good luck on your test tomorrow!

OpenStudy (anonymous):

Thanks! I understand doing it the long way to see the process. I just worry that I would make an error.

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