Ask your own question, for FREE!
Mathematics 16 Online
OpenStudy (anonymous):

1 multiple choice geometry question help will fan and medal

OpenStudy (anonymous):

OpenStudy (anonymous):

use polar co-ordinate system to describe the same position, you know that?

OpenStudy (anonymous):

nope

OpenStudy (anonymous):

well, in polar co-ordinate system, you assume an axis (say here x axis), the point's position vector is described by (r,theta) , where r is the distance from the origin and theta is the angle it made with the axis

OpenStudy (anonymous):

Can you solve the problem for me stpe by step then I can take in all the information

OpenStudy (anonymous):

so, you know how to calculate the distance from the origin using pythagoras theorem right?

OpenStudy (anonymous):

I think so yes

OpenStudy (anonymous):

@samsterz , can you calculate the distance of the point (20,-6) from the origin?

OpenStudy (anonymous):

ok, then try and tell me what the answer is

OpenStudy (anonymous):

ok now what about the degrees part

OpenStudy (anonymous):

you can see clearly, if the line joining the origin and the point makes angle theta with the axis, then \[\tan \theta=-6/20\] hence, \[\theta=\tan^{-1} (-6/20)\] calculate

OpenStudy (anonymous):

the polar co-ordinate position will be (distance, theta)

OpenStudy (anonymous):

anyway, you have to calculate that theta value by radian

OpenStudy (anonymous):

i got 21 miles at 17 degrrees south fo east, what did u get?

OpenStudy (anonymous):

how much is 17 degree by radian?

OpenStudy (anonymous):

0.297 radians

OpenStudy (anonymous):

that's correct, so the position vector can be written as (21, -0.297) in polar co-ordinate system

OpenStudy (anonymous):

so my answer was right

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

thank you :) for your help arnab

OpenStudy (anonymous):

you are welcome :) glad to help

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!