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Physics 17 Online
OpenStudy (anonymous):

A bomb is dropped from an aeroplane moving horizontally with a speed of 200 m/hr if the air resistance is negligible if the bomb will reach in ground in 5 sec when the altitude of the plane is approximately a 80ft b 400ft c 800ft d100ft @kropot72

OpenStudy (anonymous):

ye konsi book se prh ri ho?

OpenStudy (anonymous):

@CO_oLBoY any idea ?

OpenStudy (anonymous):

ya i think height of projectile ka formula lage ga

OpenStudy (anonymous):

try to solve it

OpenStudy (anonymous):

?

OpenStudy (anonymous):

ho jaye ga kr k dekh lo

OpenStudy (anonymous):

theta ?

OpenStudy (mrnood):

The horizontal motion is irrelevant in this case. The bomb drops with a vertical acceleration of g you know that the initial (vertical) velocity is 0 you know that time = 5s the equation for this is s=ut + 0.5*a* t^2 so use this equation to solve for s (s is the distance travelld = height of plane) @sarah786 - Everything you need to answer this is given above - I will not give you the answer

OpenStudy (anonymous):

han is tareeqe se aram se ho jaye ga

OpenStudy (anonymous):

@MrNood I also dun want direct answers .

OpenStudy (anonymous):

but first i have to convert m/hour in m/sec

OpenStudy (mrnood):

no The horizontal velocity is irrelevant. The answer would be the same if the bomb was dropped from a hot air balloon which had 0 velocity.

OpenStudy (anonymous):

Oh I got it . I was thinking about a but a = g here . :)

OpenStudy (mrnood):

However - you do need to use the correct units for g g = 9.81 m/s^2 = 32 ft/s^2

OpenStudy (anonymous):

oh I dun think about this one .that's why my answer is not coming . :O

OpenStudy (anonymous):

its B 400ft

OpenStudy (anonymous):

Thank you so much for ur help @MrNood ^_^

OpenStudy (mrnood):

np :-)

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