(x^2 + 1)(x^3 + 2x)(x^2 + 4x - 16i - 4xi) = 0
Solve the following equation by identifying all of its roots including any imaginary numbers. In your final answer, include the necessary steps and calculations.

Question

(x^2 + 1)(x^3 + 2x)(x^2 + 4x - 16i - 4xi) = 0
Solve the following equation by identifying all of its roots including any imaginary numbers. In your final answer, include the necessary steps and calculations.

anonymous · Answer

set each factor equal to zero and solve

anonymous · Answer

for example 
$$x^2 + 1=0\
x^2=-1\
x=\pm\sqrt{-1}\x=\pm i$$ for the first factor

anonymous · Answer

$$x^2 + 4x - 16i - 4xi=0$$ will present a challenge but if you rewrite it as $$x^2+(4-4i)x-16i=0$$ you can use the quadratic formula with $$a=1,b=4-4i,c=-16i$$

anonymous · Answer

Thank you very much. Do I have to do anything else or is everything you wrote is the answer?

anonymous · Answer

@satellite73