Question

Integral of [sec (tan y - sec y)] dy pls help me :(

Answer 1

is your statement correct?

Answer 2

oops my bad it's sec y(tan y - sec y) dy

Answer 3

substitute tan y-sec y=t
\[\left( \sec ^2y-\sec y \tan y \right)dy=dt,-\sec y \left( \tan y-\sec y \right)dy=dt\]
you can complete it.

Answer 4

\[I=\int\limits \left( -dt \right)+c=-t+c\]

Answer 5

Oh okay! Thanks! I understand it now :)

Answer 6

yw