Refreshing my memory again, but with triangles?

Question

anonymous · Answer

Two triangles can be formed with the given information. Use the Law of Sines to solve the triangles.

A = 55°, a = 12, b = 14

anonymous · Answer

How do I find the second one again? @phi

anonymous · Answer

@satellite73

anonymous · Answer

@surjithayer ?

anonymous · Answer

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anonymous · Answer

I can figure the first one, but I can never remember how to fins the second one!

anonymous · Answer

<C+55+ <B=180
if you know <B, then you can find <C

anonymous · Answer

That's the second triangle???

anonymous · Answer

where is the data for second triangle?

phi · Answer

finding the two ambiguous triangles can be confusing.
notice when you solve for angle B, you set up this ratio
$$ \frac{\sin 55}{12}= \frac{\sin B}{14} $$
multiply both sides by 14 to get
$$  14\cdot \frac{\sin 55}{12}= \sin B \
\sin B = \frac{7}{6} \sin 55 \ \sin B= 0.95568
$$

You should always keep in mind the graph of the sin, between 0 and 180º (these are the angles that might be in a triangle).  It looks like this:
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