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*.*.*.*.*.*I will give medal*.*.*.*.*.* How can sine's rule be used in this???
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You mean: For any triangle ABC, \(\dfrac{\sin A}{a}=\dfrac{\sin B}{b}=\dfrac{\sin C}{c}\) ?
|dw:1401736583119:dw| Find all letters.
Start with the Law of Cosines.
no i need sine rule
You have two unknowns that way. You need to start with Cosines to get it to one unnown, then use sines.
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ok so can u help me out
So, do you know the Law of Cosines?
\[c ^{2}=a ^{2}+b ^{2}-2ab \cos C\] \[c=\sqrt{(7^{2}+8^{2}-2(7)(8)\cos 50)}\] \[c=6.404\] is this right
I got 6.40373232694, so yah.
|dw:1401737225445:dw|
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ok now i can do it thanks.
Now you can use that and sines to find \(\angle A\).
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