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Mathematics 13 Online
OpenStudy (anonymous):

First Question Of The Day (F.Q.O.F.D.)

OpenStudy (anonymous):

OpenStudy (anonymous):

@anteater

OpenStudy (anonymous):

@Hero

OpenStudy (anonymous):

the formula for this is [1/3 (Base area) height ] 2

OpenStudy (anonymous):

you can slove it by plugging in the values and doing it out.

OpenStudy (anonymous):

Wait, did you put 1/3 * 5.7 * 3^2?

OpenStudy (anonymous):

it's the base area not the edge length so what do you think it would be?

OpenStudy (anonymous):

I'm not quite sure what's the base area, all I know is the height is 3 and the base length is 5.7. Also, the formulas as well which is; 1/3 (b^2) (h)

OpenStudy (mrnood):

Remember - it is TWO pyramids stuck together..... btw: base area = b^2

OpenStudy (anonymous):

so it would be [1/3 (5.7x5.7) 3] 2 make sense?

OpenStudy (anonymous):

Yes, I understood that. If I or we split those two pyramids both has a base length of 5.7. Correct?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Oh okay, so I was missing another 5.7 into the equation. Okay, let me give you an answer to that.

OpenStudy (anonymous):

you're right! now, do it out. (preferably with a calculator)

OpenStudy (anonymous):

I got 97.47.

OpenStudy (anonymous):

what equation did you use again?

OpenStudy (anonymous):

\[1/3 (5.7*5.7) 3^2\]

OpenStudy (anonymous):

not \[3^{2}\]

OpenStudy (anonymous):

Oops. Will it be 1/3 (5.7*5.7)^2 3

OpenStudy (anonymous):

just the 3. do that out and then you multiply the answer by 2 to get the full shape. the first answer will be only half of it.

OpenStudy (anonymous):

no squared!!!

OpenStudy (anonymous):

Okay, give me a minute.

OpenStudy (anonymous):

32.49

OpenStudy (anonymous):

Then I multiplied it by 2 and got 64.98. But then I have to round it up, so it'll be 65.

OpenStudy (anonymous):

PERFECT!

OpenStudy (anonymous):

THATS RIGHT! GOOD JOB! :D

OpenStudy (anonymous):

Okay, I have another question that I'll be posting. You don't mind if you could help me with that?

OpenStudy (anonymous):

comment my name and i'll see what i can do.

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