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Mathematics 13 Online
OpenStudy (anonymous):

Solve 36n^2=1 by factoring

OpenStudy (imstuck):

If you have to factor this, you need to get it into semi-standard form by setting it equal to 0. You do not have a n term, just an n^2 and a constant but it can still be done. Get it into standard form\[36n ^{2}-1=0\]Now what you have is the difference between two perfect squares. So it will factor into (x + 1)(x - 1). The solutions are 1 and -1. See that?

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